Mathematics, 22.06.2019 04:10, wubzwaters
If jobs arrive every 15 seconds on average, what is the probability of waiting more than 30 seconds?
Answers: 3
is given by :-
![P(X\geq0.5)=1-P(X\leq0.5)\\\\=1-\int^{0.5}_{0}4e^{-4t}dt\\\\=1-[-e^{-4t}]^{0.5}_{0}\\\\=1-(1-e^{-2})=1-0.86=0.14](/tpl/images/0002/7489/88a18.png)
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If jobs arrive every 15 seconds on average, what is the probability of waiting more than 30 seconds?...
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