Tickets for harlem globetrotters show costs $16, $23, or, for vip seats, $40. nine times as many $16 tickets were sold as vip tickets, and the number of $16 tickets sold was 55 more than the sum of the $23 tickets and vip tickets. the total sales of all three tickets were $46,575. how many of each kind of tickets were sold?

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!

73.0769230769% of the games were won