Ramon invested $2,400 into two accounts. one account paid 3% interest and the other paid 6% interest. he earned 5% interest on the total investment. how much money did he put in each account?

In the account that paid 3% Ramon put

In the account that paid 6% Ramon put

Step-by-step explanation:

we know that

The simple interest formula is equal to

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

substitute

solver for x

Simplify

therefore

In the account that paid 3% Ramon put

In the account that paid 6% Ramon put

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

i believe the answer is 323 ft

step-by-step explanation: