In 2006, chris bought a new boat for $34,500. the boat was worth $24 500 in the year 2009. if chris knows that the value of the boat depreciated linearly, what was the annual rate of change of the boat's value? round your answer to the nearest hundredth if necessary

depreciation is $3,333.33 per year

Step-by-step explanation:

Initially : date = 2006, worth = $34,500

Finally : date = 2009, worth = $24,500

if we let x = date and y = worth, we end up with two points (coordinates) on the x-y graph

i.e

Initial = Point 1 (2006, 34500)

Final = Point 2 (2009, 24500)

The rate of change is simply the slope, m of the line joining these two points

given by:

m = (34500 - 24500) / (2006-2009)

= 10000 / -3

= -3,333.33

hence the annual rate of depreciation is $3,333.33 per year

answer: a video game has three difficulty levels: easy, medium, and expert. the game's scoring works in such a way that a player has to score a fixed number of points to advance to the next level, and then the scoring starts over. the total score needed to clear all three difficulty levels is 7,500. two times the number of points needed to clear the easy level is 500 more than the number of points needed to clear the medium level. twice the number of points needed to clear the medium difficulty level is 1,500 more than the number of points needed to clear the expert level. if x, y, and z represent the easy, medium, and expert levels, respectively, and a is the coefficient matrix of the system of equations modeling this situation, identify the inverse matrix, a-1, and the solution matrix, x, of the system of equations.

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answers

rauschg

rauschg · hand

know the answer? add it here!

step-by-step explanation:

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9