The angles of depression of two points on the ground with respect to a hot-air balloon 4 miles up in the air are 13 degrees and 39 degrees. how far apart are the two points if they lie on a straight line that passes through the point on the ground that is directly below the balloon? round your answer to four decimal places.

26.2655 miles

Step-by-step explanation:

Whenever possible, draw a diagram.  I've attached a picture of the balloon and the lines of depression (not drawn to scale, of course).

As you can see, the angles of depression form alternate interior angles with the ground (angles of elevation).  So these angles are also 13° and 39°.

We can use the tangents of these angles to find the base lengths of the two triangles that are formed.

tan 13° = 4 / a

a = 4 / tan 13°

tan 39° = 4 / b

b = 4 / tan 39°

So the total distance is:

a + b

= 4 / tan 13° + 4 / tan 39°

≈ 22.2655

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05

easy its decreasing

step-by-step explanation:

because its top point is at the to of the graph on the left side (atleast from the veiw i see it) now if that top point wast in the lower part of the graph it would be increasing hope this have a nice day