F(x)=|x-5|+2 evalute f(3)a.10b.6c.4d.0

f(3)=|3-5|+2

f(3)= |-2|+2

f(3)= 2+2

f(3)= 4

Whenever there is a negative number for the absolute value the number becomes a positive number.

Answer is f(3)= 4 ( C.)

domain is all the x values included in the

0 ≤ x ≤ 2

range is all the y values of the graph

-2 ≤ y ≤ 2

***keep in mind that there are different ways to show domain and range

hope this !

~just a girl in love with shawn mendes