Ajar contains 10 blue marbles, 6 red marbles, and 3 yellow marbles. cindy picks two marbles at random, without replacement. which product gives the probability that both of cindy's choices be red marbles? a) 6/19 × 5/19 b) 6/19 × 6/19 c) 6/19 × 5/18 d) 6/19 × 6/18

Explanation:

There are 6 red marbles out of 10+6+3 = 19 total. So 6/19 is the probability of picking one red marble. If that marble is not replaced, then we have 6-1 = 5 red marbles left out of 19-1 = 18 total. The probability of picking another red is 5/18

We have 6/19 as the probability of picking red the first time, then 5/18 as the probability of picking another red marble. The first marble is not put back, and that marble is not replaced.

In terms of math notation, we can say

A = event of picking red on the first selection

B = event of picking red on the second selection

P(A) = 6/19

P(B|A) = 5/18

P(A and B) = P(A)*P(B|A)

P(A and B) = 6/19 * 5/18

answer: 5100 just subtract

step-by-step explanation:

something over 10 so ? /10

step-by-step explanation: