Mathematics

Mathematics, 23.06.2019 10:40, BigGirlsTheBest

What is the standard form of $y + 2 = \frac{1}{2} (x - 4)$

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English, 24.06.2019 00:30, dayana72

What do the fourth, fifth, sixth, seventh, and eighth amendments guarantee for citizens? ability to bear arms freedom of speech a fair trial right to vote[tex]\frac{x}{y}\frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{xfdddddddddddddddddddddddddddddddd}{y}[/tex]

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Mathematics, 02.07.2019 19:30, joshuaburge13

Can someone me solve an algebra equation? direction: write each equation in *standard form*. [tex]\frac{3}{5}x+ \frac{1}{4} y=-\frac{1}{2}[/tex]

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Mathematics, 14.07.2019 01:30, wiintrr30

[tex] \frac{(a-3) * (\frac{a}{3} +1)}{\frac{1}{3}} [/tex] [tex] \frac{a( \frac{a}{3} ) + a - 3(\frac{a}{3}) - 3 }{\frac{a}{3}} [/tex] [tex] \frac{\frac{3a+a}{3} + a - 3 * \frac{a}{3} - 3}{\frac{1}{3}} [/tex] [tex] \frac{\frac{4a}{3} + a - a - 3}{\frac{1}{3}} [/tex] [tex] \frac{4a}{3} / \frac{1}{3} - 3 / \frac{1}{3} [/tex] [tex] \frac{4a}{3} * 3 - 3 * 3 [/tex] [tex] 4a - 9 [/tex] yet the answer i should get is [tex] a^{2}-9 [/tex]. what step am i doing wrong on this algebra problem?

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Mathematics, 01.08.2019 16:00, jedmnlp5xuks

Answer the questions 2) [tex] \frac{1}{20} \div \frac{4}{5 } = [/tex]3) [tex]10 \times \frac{1}{2} \div 3 \times \frac{1}{5 } = [/tex]4) what is the reciprocal of 4? 5) what is the reciprocal of [tex]4 \times \frac{5}{8} [/tex]6) how can you check that this is correct[tex] \frac{5}{8} \div \frac{2}{3} = \frac{15}{16} [/tex]a) [tex] \frac{15}{16} \div \frac{2}{3} = \frac{5}{8} [/tex]b)[tex] \frac{15}{16} \div \frac{5}{8} = \frac{2}{3} [/tex]c)[tex] \frac{3}{2} \times \frac{15}{16} = \frac{5}{8} [/tex]d)[tex] \frac{2}{3} \times \frac{15}{16} = \frac{5}{8} [/tex]7) [tex] \frac{3}{4} \div \frac{1}{8} = [/tex]8) [tex]9 \times \frac{3}{4} \div \frac{3}{4} = [/tex]9) all of the parts to this question is in the picture

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What is the standard form of [tex]y + 2 = \frac{1}{2} (x - 4)[/tex]...

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