23x² +8x+ 5-14which constant would you add to the right side of thequadratic equation in order to solve by completing thesquare? remember, this is a two-step process

ANSWER

The correct answer is D

EXPLANATION

The given quadratic expression is

Divide through by 3

We now add the square of half the coefficient of x because the coefficient of the quadratic term is now unity.

The constant we would add is

The correct answer is D

Option D.

Step-by-step explanation:

Given the quadratic equation , you can observe that the leading coefficient is not 1, then you have to divide both sides of the equation by 3:

Now, you can observe that the coefficient of the x-term is , so you must divide it by 2 and square it. Then you get:

Therefore, you must add to both sides of the equation.

answer4 to the second power is 16

and 4 to the third power is 64,

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.