Solve the following system of equations by using the elimination method. 2x + 4y = 8 and 3x – 3y = 12

  (x, y) = (4, 0)

Step-by-step explanation:

It is convenient to first put the equations into standard form by eliminating common factors. The first equation has a factor of 2 that can be removed; the second equation has a factor of 3 that can be removed. Then you have ...

Subtracting the second equation from the first eliminates the x variable. That gives you ...

  (x +2y) -(x -y) = (4) -(4)

  3y = 0 . . . . . . simplify

  y = 0 . . . . . . . divide by 3

Substituting this value into either equation above, you get ...

  x + 0 = 4

  x = 4

The solution is (x, y) = (4, 0).

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right