What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (-4,-3)? 54-3-2-11 2 3 4 5 o y + 3 = -4(x + 4) oy+3= 2(x+4) y+ 3 = (x + 4) y + 3 = 4(x + 4)

y + 3 = -4(x + 4)

Step-by-step explanation:

This is because point slope form is (y-k) = m(x-h) where h and k are the coordinates and m is the slope so by plugging it in you get y+3 = -4(x+4)

(pls mark brainliest)

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5