The graph of the even function f(x) has five x-intercepts. if (6, 0) is one of the intercepts, which set of points can be the other x-intercepts of the graph of f(x)? (–6, 0), (–2, 0), and (0, 0) (–6, 0), (–2, 0), and (4, 0) (–4, 0), (0, 0), and (2, 0) (–4, 0), (–2, 0), and (0, 0)

answer: all the values are within because it has a pattern that repeats from -6 to 4.

good luck!

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

the formula of a slope:

we have the points (-2, 7) and (2, 3). substitute: