So reflections if p= (3,4), find: ry=5 (p)

The reflected point is (3,6)

Step-by-step explanation:

we know that

The reflection Ry = 5, means a reflection is across the line y= 5

we have

the point P(3,4)

Since the point P has y-coordinate  4, its distance to the line y= 5 is equal to 1 units (P is located 1 units down the line y=5).

therefore

The reflection of the y-coordinate will be 1 units above the line y=5, which is  equal to

5+1=6

Hence

the y-coordinate of the image is 6.

The reflected point is (3,6)

i need the options

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3