Which exponential function goes through the points (1,32) and (4,2048)

y=8*4^x

Step-by-step explanation:

Let the exponential function be of the form y=A*B^x

We want to find constant A and B.

So I'm going to use (1,32) giving me 32=A*B

I'm going to use (4,2048) giving me 2048=A*B^4

2048/32=64

A*B^4/A*B=B^3

So If you divide the equation 2048=A*B^4 by 32=A*B

we get 64=B^3

which gives us B=4

Since 32=A*B and B=4 then A=8

So the answer is y=8*4^x

24

step-by-step explanation: