(w - 2.5)(w + 2.5)
(-4v - 9)(-4v + 9)
Step-by-step explanation:
* Lets explain what is the a difference of two squares
- If we multiply two binomial and the answer just two terms with
Β negative sign between them and the two terms are square numbers
Β we called this answer a difference of two squares
- Examples
# (a + b)(a - b)
- Lets multiply them
β΅ (a Γ a) + (a Γ -b) + (b Γ a) + (b Γ -b)
β΄ aΒ² - ab + ba - bΒ²
- Add the like term
β΅ ab = ba
β΄ -ab + ba = 0
β΄ (a + b)(a - b) = aΒ² - bΒ² β difference of two squares
- From above the difference of two squares appears when we
Β multiply sum and difference of the same two terms
# (a + b) β is the sum of a and b
# (a - b) β is the difference of a and b
* Now lets solve the problem
- In (5z + 3)(-5z - 3)
β΅ (5z + 3) β is the sum of 5z and 3
β΅ (-5z - 3) β is the difference of -5z and 3
β΅ 5z β - 5z
β΄ They are not the sum and difference of the same two terms
β΄ The product result not in a difference of squares
- In (w - 2.5)(w + 2.5)
β΅ (w - 2.5) is the difference between w and 2.5
β΄ (w + 2.5) is the sum of w and 2.5
β΄ They are the sum and difference of the same two terms
β΄ The product result in a difference of squares
- In (8g + 1)(8g + 1)
β΅ The two brackets are the sum of 8g and 1
β΄ They are not the sum and difference of the same two terms
β΄ The product result not in a difference of squares
- In (-4v - 9)(-4v + 9)
β΅ (-4v - 9) is the difference between -4v and 9
β΅ (-4v + 9) is the sum of -4v and 9
β΄ They are the sum and difference of the same two terms
β΄ The product result in a difference of squares
- In (6y + 7)(7y - 6)
β΅ (6y + 7) is the sum of 6y and 7
β΅ (7y - 6) is the difference between 7y and 6
β΅ 6y β 7y and 7 β 6
β΄ They are not the sum and difference of the same two terms
β΄ The product result not in a difference of squares
- In (p - 5)(p - 5)
β΅ The two brackets are the difference of p and 5
β΄ They are not the sum and difference of the same two terms
β΄ The product result not in a difference of squares
