Triangle abc is translated on the coordinate plane below to create triangle a'b'c': triangle abc, triangle a prime b prime c prime, and parallelogram efgh on the coordinate plane with ordered pairs at a negative 7, negative 2, at b negative 5, negative 5, at c negative 1, negative 5, at a prime negative 4, 4, at b prime negative 2, 1, at c prime 2, 1, at e 3, 6, at f 7, 6, at g 5, 3, at h 1, 3. if parallelogram efgh is translated according to the same rule that translated triangle abc, what is the ordered pair of point h'?

graph b

step-by-step explanation:

one solution- graph a (clear intercepting point.)

no solution- graph b (they're parallel, there will never be a point of interception.)

infinite solutions- graph c (all points intercept.)

      2

  2 is to go somewhat to the top right of a because it is squared    

v= a h/3

look at the picture.

1.

ef : ab = 2 : 3

gf : cb = 2 : 3

gh : cd = 2 : 3

he : da = 2 : 3

2.

∠a ≅ ∠e

∠b ≅ ∠f

∠c ≅ ∠g

∠d ≅ ∠h

3.

use pythagorean theorem:

the length of the abcd trapezoid sides:

|ab| = 3 cm

|bc| = 10 cm

|cd| = 3(3) cm = 9 cm

|da| = 8 cm

the perimeter of abcd = 3 + 10 + 9 + 8 = 30 cm

the ratio of perimeters of the tarapezoids is equal 2 : 3.

substitute:

      cross multiply

      divide both sides by 3