If t: (x, y) → (x - 3, y + 2), then t -1: (x, y) → (x + 3, y + 2) (x + 3, y - 2) (, -) (3x, -2y)

(x + 3, y - 2)

Step-by-step explanation:

we know that

The rule of the transformation T is equal to

T: pre-image → image

T: (x, y) → (x',y')

T: (x, y) → (x - 3, y + 2)

so

x'=x-3 > x=x'+3

y'=y+2 > y=y'-2

The rule of the inverse of transformation T -1 is equal to

T-1: image → pre-image

T-1: (x', y') → (x,y)

T-1: (x', y') → (x'+3, y'-2)

right

step-by-step explanation:

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b