Atoy rocket is launched straight up into the air with an initial velocity of 60 ft/s from a table 3 ft above the ground. if acceleration due to gravity is –16 ft/s2, approximately how many seconds after the launch will the toy rocket reach the ground? h(t) = at2 + vt + h0

it will take appr 3.8 seconds to hit the ground

Step-by-step explanation:

h = -16t^2 + 60t + 3

at ground level , h = 0

16t^2 - 60t - 3 = 0

t = (60 ± √3792)/32

t = 3.799.. or t = a negative

c: y > - 1/6x + 1

step-by-step explanation:

dashed line - meaning this < or > also not equal

solid line - meaning this < or > also equal

your answer is c because y > means up & it's shaded up, but y < means down

hope this ! : )