Let a(t)=[3sin(t)3 sin(t)−4 cos(t)4 cos(t)]. find the values of t such that a(t) is not invertible. you may use k to denote any possible integer in your answer (e. g., if the answer is all integer multiples of 5, you would enter 5k, where k is any integer). a(t) is not invertible when t= k*pi/2 , where k is any integer. find a formula for a−1(t) for the values of t for which a(t) is invertible. a−1(t)= ⎡⎣⎢⎢⎢ ⎤⎦⎥⎥⎥

correct

step-by-step explanation:

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

d. all of the above

step-by-step explanation: