The width of a rectangle is 30% of the length. the perimeter of the rectangle is 338 ft. find the length and width of the rectangle

L=130 while W=39

Step-by-step explanation:

Let's setup some equations.

W=.3L  from first sentence

2L+2W=338 from second sentence

I'm going to plug equation 1 into equation 2:

2L+2[.3L]=338

2L+.6L=338

2.6L=338

L=338/2.6

L=130

so W=.3L=.3(130)=39

Answer L=130 while W=39

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

read more on -

a

step-by-step explanation:

a