The cost to rend a construction crane is $750 per day plus $250 per hour of use. write an inequality that can be used to find the maximum number of hours, h the crane can be used each day without exceeding $2500 per day.

750 + 250h ≤ 2500

Step-by-step explanation:

First, we must set up an equation. We know that the initial value is $750 per day and the rate is $250 for H, hours. Putting this into an expression, we get

750 + 250h

We also know that the total cost per day cannot exceed $2,500. However, the total cost can reach $2,500. Because the cost can go up to $2,500, the expression 750 + 250h must be less than or greater than $2,500 because although the cost can be cheaper than $2,500, the cost may reach $2,500. It just can't go above it.

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4

the answer is 150.6

step-by-step explanation:

you multiply .02 by 30 and get .6.

and then you multiply 5.00 by 30 and get 150.

hope this !