Two secants meet outside the circle, forming an angle of 42 degrees. if the larger intercepted arc is 120 degrees, find the smaller intercepted arc

36°

Step-by-step explanation:

An angle whose vertex lies outside a circle whose sides are 2 secants of the circle is

angle = ( larger arc - smaller arc ), that is

42 = ( 120 - smaller ) ← multiply both sides by 2

84 = 120 - smaller, hence

smaller = 120 - 84 = 36°

i got 10.28 but that rounds up to 10.3

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15