A52 year-old father has a son and a daughter. the son is twice as old as the daughter. in 4 years the sum of all their ages will be 100. how old are the two siblings now? (rsm problem)

The age of daughter is 12 years  and age of son is 24 years

Step-by-step explanation:

Given :

Present age of father = 52 years

Let the present age of daughter be x

So according to the question son's age is twice that of daughter's

So present age of son =2x

Now after 4 years the sum of their ages = 100

i.e. x+4 + 2x+4 + 52 +4 =100

3x+ 64 = 100

Subtracting both sides by 64 we get

3x + 64 - 64=100 -64

3x = 36

Dividing LHS and RHS by 3 we get

x=12

i.e. Present age of daughter  = x = 12 years

Present age of son = 2x = 2× 12= 24 years

the answer is option a you would get more money.it would be $250.

step-by-step explanation:

for option b 200/2=100=50% 100/2=50=25% 50/5=10=5% it would be $220

what steps are you having us

step-by-step explanation: