You want to endow a scholarship that will pay $10,000 per year forever, starting one year from now. if the school’s endowment discount rate is 7%, what amount must you donate to endow the scholarship? 13. how would your answer to problem 12 change if you endow it now, but it makes the first award to a student 10 years from today?

12. $142,857.14

13. $77,704.82 . . . it is changed by the accumulated interest on the amount

Step-by-step explanation:

12. You want one year's interest on the endowment to be equal to $10,000. The principal (P) can be found by ...

  I = Prt

  10,000 = P·0.07·1

  10,000/0.07 = P ≈ 142,857.14

The endowment must be $142,857.14 to pay $10,000 in interest annually forever.

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13. If the first award is in 10 years, we want the above amount to be the value of an account that has paid 7% interest compounded annually for 9 years. (The first award is 1 year after this amount is achieved.) Then we want the principal (P) to be ...

  142,857.14 = P·(1 +0.07)^9

  142,57.14/1.07^9 = P = 77,704.82

The endowment needs to be only $77,704.82 if the first award is made 10 years after the endowment date.

dont trust me im no expert these losers made me fail a test bro this sucks

step-by-step explanation:

tell you what. i'll find the length of the medians and you can fill in the blanks where they belong.

br

b = (2a,0)

r = (a/2,b/2) remember these things are medians. they go to the 1/2 way point of the line opposite the vertex they face.

br^2 =   (2a - a/2)^2 + (0 - b/2)^2

br^2 = (3/2 a) ^2 + b^2 / 4

br^2 = 9/4 a^2 + b^2 / 4   we need to find some relationship between a and b.

let's try ab = bc  

ab = 2a

bc = (2a - a)^2 + (b - 0)^2

bc = sqrt(a^2 + b^2)

ab = bc

2a = sqrt(a^2 + b^2) square both sides.

4a^2 = a^2 + b^2 subtract a^2 from both sides.

sqrt(3a^2) = sqrt(b^2)

sqrt(3)a = b

let's put b into br^2

br^2 = 9/4 a^2 + 3b^2 / 4

br^2 = 12 a^2 / 4

br^2 = 3a^2 

br = sqrt(3) * a

cp

c = (a,b) ; p = (a,0) this is another application of the distance formula, and it is a good one.

cp^2 = (a - a)^2 + (b - 0)^2

cp^2 = 0 + b^2

cp^2 = b^2 which you can see from the diagram. 

cp = sqrt(b^2)

cp = b but b = sqrt(3) * a 

cp = sqrt(3)*a

aq

a = (0,0)

q = (3/2) a, b/2

aq^2 = (3a/2 -0)^2 + (b/2 - 0)^2

aq^2 = 9a^2/4 + b^2/4

but b = sqrt(3) * a 

aq^2 = 9a^2 / 4 + (sqrt(3)*a)^2 /4

aq^2 = 9 a^2/ 4 + 3 a^2 / 4

aq^2 = 12 a^2/4

aq^2 = 3 a^2

aq = (sqrt  3) * a which agrees with the other two.