Which is an equation of a circle with center ( -5, -7) that passes through the point ( 0, 0 )

(x+5)^2+(y+7)^2=74

Step-by-step explanation:

So we are given this (x+5)^2+(y+7)^2=r^2

We need to find r so just plug in your point (0,0) for (x,y) and solve for r :)

(0+5)^2+(0+7)^2=r^2

25+49=r^2

74=r^2

So the answer is (x+5)^2+(y+7)^2=74

step-by-step explanation:

vyv6vycyctxrd4ff6fg yr x5dc v6y555 vyuvu

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)