What is the best interpitation of v(4)=64

When x=4, y=64

Step-by-step explanation:

I'm going to use f(x)=y instead of the letters you have given so the problem would look like f(4)=64. The number in the parentheses, (x), will always be for when x=?. The number on the other side of the = is y=?.

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0