An article in technometrics (vol. 19, 1977, p. 425) presents the following data on the motor fuel octane ratings of several blends of gasoline: 88.2 99.8 88.8 91.6 92.9 91.3 90.4 91.9 95.6 88.9 90.1 83.5 87.7 87.7 88.0 90.8 83.9 90.1 91.4 91.9 93.7 91.6 87.6 89.9 91.1 91.7 90.1 87.3 93.8 93.0 87.7 92.4 88.3 89.8 89.1 88.9 91.1 97.1 89.7 89.2 88.9 91.4 88.3 93.5 90.9 84.1 92.7 92.8 90.7 88.2 95.0 87.0 90.3 93.6 89.9 90.9 91.5 86.3 90.6 87.6 88.5 90.3 89.8 86.1 89.6 90.2 93.2 87.9 93.3 91.9 92.8 89.8 100.4 90.1 93.1 93.6 89.3 95.2 91.2 88.5 89.7 88.6 85.7 calculate the sample median, mode, and mean of these data.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

30 miles

step-by-step explanation:

we know that 60 seconds equals 1 minute and 60 minutes 1 hour

44 ft       60 sec     60 min     158400   ft

  *   *   =

1 sec       1 min       1 hour         hour

we know that there are 5280 ft per mile

158400   ft       1 mile         30 miles

  *   =

1   hour               5280 ft     1 hour

so in 1 hour   it can travel 30 miles

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(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3