What is the range of the function f(x) = 3x - 12 for the domain (-2, 2)? a. (3,12) b. 4-6, -18) c. (6, 18) d. (12,3)

When x=-2

f(x) =3(-2) -12 =-6-12=-18

When x=2

f(x) = 3(2)-12=6-12=-6

So For the domain (-2,2)

Range of the function f(x) is (-18,-6)

So (-18 ,-6). is your answer.

Hope it helps

Regards,

Leukonov/Olegion.

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

⭐⭐

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3