Kelly raised a number 2 to a power and then added 4 to the result. she obtained a sum of 68. to what power did she raise 2?

2 to the 6th power.

Step-by-step explanation:

2^x + 4 =68

2^x = 64

x= 6

8

Step-by-step explanation:

In order to solve this problem, you have to create your own equation.

Step 1) Assign a variable to the mystery number. For this example, we'll just call it "n"

Step 2) Just as in the question, raise the variable "n" to the power of 2, or n squared

Step 3) Since the equation says that after squaring "n", Kelly added four to the squared number, you'll write out [n squared] + 4 = [the final result, or 68)

Then, you should get the equation

n(^)2 + 4 = 68

Next, you'll evaluate the equation as follows:

Step 1) Subtract 4 from both sides of the equation to get rid of the number four on the left side and get: n^2 = 64

Step 2) n * n is the same thing as n squared, so in order to get "n" by itself, root each side of the equation to get: n = 8. Remember that the root of a number is a number that, multiplied by itself, equals the original number (for example, 2*2 = 4, 5*5 = 25, etc.)

Thus, n = 8, which is the number that Kelly raised to the power of two. You can check this by replacing "n" in our written equation with 8, which will get you: 68 = 68. Since the numbers on both sides of the equation are the same, the equation is true.

idk

step-by-step explanation:

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!