Write an equation of a line in slope-intercept form that is perpendicular to the line 2x -3y = 12 and passes through the point (2, 6).

For this case we have by definition, that the equation of a line in the slope-intersection form is given by:

Where:

m: It's the slope

b: It is the cutoff point with the y axis

We have the following line:

If the line we wish to find is perpendicular to the one given, then its slope is given by:

Then the line is:

We substitute the point:

Finally, the equation is:

a=r

d=q

c=p

b=s

hope this !

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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