Lucy has two star systems left to visit on her voyage, but her ship is running low on fuel. the first system, ka- 7 77, is 1 2 0 0 12001200 light years ( l. y. ) (l. y.)left parenthesis, l, point, y, point, right parenthesis away while the second system, ka- 1 1 1111, is 1 7 0 0 l. y. 1700 l. y.1700, space, l, point, y, point. her top priority is to visit star system ka- 7 77. to determine if she'll also be able to visit ka- 1 1 1111, she must find the distance between ka- 7 77 and ka- 1 1 1111. if lucy sees an angle of 5 2 ∘ 52 ∘ 52, degree between ka- 7 77 and ka- 1 1 1111, how far are ka- 7 77 and ka- 1 1 1111 apart?

step-by-step explanation:

20% of 120 is 24. if you subtract 24 from 120 you get 96

4

step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.