At 6: 00 a. m. the temperature was 33°f. by noon the temperature had increased by 10°f and by 3: 00 p. m. it had increased another 12°f. if at 10: 00 p. m. the temperature had decreased by 15°f, how much does the temperature need to rise or fall to return to the original temperature of 33°f?

The temperature needs to decrease by 7°F to return to the original temperature.

Step-by-step explanation:

The temperature starts at 33 degrees then increases by 10 then 12 then decreases by 15 which will equal 40.

33 + 10 = 43

43 + 12 = 55

55 - 15 = 40

40 - 33 = 7

The temperature needs to decrease by 7 degrees.

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1

2 x 503

step-by-step explanation:

its 1006