Function a is a quadratic function with a vertex at (3, 4) and a leading coefficient of -1 function b has the equation y = |x + 2|. function a is then reflected over the x-axis and shifted down 2 while function b is reflected over the x-axis and shifted up 3. which function has the larger y-intercept after being transformed and by how much?

With the information given, we deduce that the parabola is

Reflecting a function over the x axis means to change its sign. After the reflection, the parabola becomes

And to shift down a function, you subtract the shift from the equation: the equation becomes

Similarly, the other function is reflected over the x axis (sign change) and shifted up 3 (add 3 to the equation):

In order to compute the y intercept, we simply have to evaluate the functions at x=0: for the parabola we have

For the other function, we have

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option