The position of a particle in the xy-plane at time t is bold r left parenthesis t right parenthesis equals left parenthesis e superscript t baseline right parenthesis bold i plus left parenthesis startfraction 7 over 25 endfraction e superscript 2 t baseline right parenthesis bold j . find an equation in x and y whose graph is the path of the particle. then find the particle's velocity and acceleration vectors at t equals ln 5.

the answer is 37

step-by-step explanation:

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x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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