Acollege-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100. using the eight‐part symmetry of the area under a normal curve, what is the probability that a randomly chosen exam score is less than 200 or greater than 800? the probability

The probability is  0.003

Step-by-step explanation:

We know that the average is:

The standard deviation is:

The Z-score is:

We seek to find

For P(x>800) The Z-score is:

The score of Z = 3 means that 800 is 3 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the conficion of 3 deviations from the mean has percentage of 0.15%

So

For P(x<200) The Z-score is:

The score of Z = -3 means that 200 is 3 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the conficion of 3 deviations from the mean has percentage of 0.15%

So

Therefore

$450.00 for 6 weeks

or

$300

step-by-step explanation:

$200.00 for first week $50.00 x5 equals $250 plus $200 equals $450.00 for six weeks.

$200 for first week

$200 x 0.10 = $20

$20 x 5 = $100

$200 + $100 = $300

range is infinite on both x and y axis positive and negative

step-by-step explanation: