Abag contains five red marbles, two orange marbles, one yellow marble, and two green marbles. two marbles are drawn from the bag. what is the approximate probability of choosing an orange marble and a green marble? 0.02222 0.04444 0.08889 0.13333

0.08889

Step-by-step explanation:

How many marbles are in the bag

5 red + 2 orange + 1 yellow + 2 green = 10 marbles

P (orange) = 2/10 = 1/5

Now there are 9 marbles

P (green) = 2/9

P (orange, green) = 1/5* 2/9 = 2/45

Since we don't care about the order, just that we have two marbles , one green one orange, we also need to find the probability that we draw, green orange

P (green) = 2/10 = 1/5

Now there are 9 marbles

P (orange) = 2/9

P (green, orange) = 1/5* 2/9 = 2/45

We add the probabilities together

2/45+2/45 = 4/45 =.088888888

0.08889

Step-by-step explanation:

d

step-by-step explanation:

answer: i think one of the answer is $150 and $300?

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