Male and female high school students reported how many hours they worked each week in summer jobs. the data is represented in the following box plots: two box plots shown. the top one is labeled males. minimum at 0, q1 at 1, median at 20, q3 at 25, maximum at 50. the bottom box plot is labeled females. minimum at 0, q1 at 5, median at 6, q3 at 10, maximum at 18 identify any values of data that might affect the statistical measures of spread and center. your the females worked less than the males, and the female median is close to q1. there is a high data value that causes the data set to be asymmetrical for the males. there are significant outliers at the high ends of both the males and the females. both graphs have the required quartiles.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

answer: 3.26019516

step-by-step explanation:

tried on you are knowing that we can't leave the picture in the graph ok no problem now you need to send it in the question group