How many real roots are in x^3 - 4x^2 + 5x a) 0 b) 3, c) 1 d) 4 e) 2

I haven't been taught this in school yet but by inputting it into desmos the door would be 0

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

idk

step-by-step explanation: