Mathematics
Mathematics, 28.06.2019 11:40, nina1390

__ _cos b =1/2[sin(a+b)+sin(a-b)] a) cos b b) sin b c) sin a d) cos a

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__ _cos b =1/2[sin(a+b)+sin(a-b)] a) cos b b) sin b c) sin a d) cos a...

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