Mrs. culland is finding the center of a circle whose equation is x2 + y2 + 6x + 4y – 3 = 0 by completing the square. her work is shown. x2 + y2 + 6x + 4y – 3 = 0 x2 + 6x + y2 + 4y – 3 = 0 (x2 + 6x) + (y2 + 4y) = 3 (x2 + 6x + 9) + (y2 + 4y + 4) = 3 + 9 + 4 which completes the work correctly? (x – 3)2 + (y – 2)2 = 42, so the center is (3, 2). (x + 3)2 + (y + 2)2 = 42, so the center is (3, 2). (x – 3)2 + (y – 2)2 = 42, so the center is (–3, –2). (x + 3)2 + (y + 2)2 = 42, so the center is (–3, –2).