The letters a, b, c, d, e, and f are written on six different ping pong balls and put into a bag. the letters h, i, j, and k are written on another four different ping pong balls and put into a second bag. then the letters o, p, q, r, s, t, and u are written on another seven different ping pong balls and put into a third bag. if one ping pong ball is randomly selected from each of the three bags, what is the probability that at least one vowel (a, e, i, o, u) is selected?

probability for j is 1/4

while

a is 1/6

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

66.666666667%

step-by-step explanation:

divide 150 by 100

divide 100 by 1.5

there you go!

decreased by 33.333333334%