40. if (5, y) is a solution to the equation 5x+4y-20=0, what is the value of y? alu co à cd

Hello there! The value of y is -5/4.

So, basically look at it like an ordered pair, (x, y). When we have (5, y), we have a value of x and are looking for a value of y. To do this, plug the value for x (5) into the equation and solve for y.

5x+4y-20=0

5(5)+4y-20=0

Now that you have the value for x, solve for y.

5(5)+4y-20=0 - Start by multiplying out the parenthesis.

25 + 4y - 20 = 0 - Next, combine like terms.

25 - 20 + 4y = 0

5 + 4y = 0 - Now, subtract 5 from both sides.

4y = -5 - Lastly, divide both sides by 4.

y = -5/4.

This is your final answer. I hope this helps and have a great day! :)

i used to know how to do this in 7th but i forget easily

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.