Given y = 4x + 3, what effect does changing the equation to y = 4x - 3 have on the y-intercept?

The y-intercept changes from (0, 3) to (0, -3)

Step-by-step explanation:

The y-intercept refers to the point where the graph of a function crosses or intersects with the y-axis. At this point, the value of x is usually 0.

Substitute x = 0 in both equations to determine how the y-intercept changes;

The original equation is given as y = 4x + 3,

when x = 0; y = 4(0) + 3 = 3

The y-intercept is thus (0, 3)

The new equation is given as y = 4x - 3

when x = 0; y = 4(0) - 3 = -3

The y-intercept is thus (0, -3)

Therefore, the y-intercept changes from (0, 3) to (0, -3)

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841