At a basketball game at team made 55 successful shots they were a combination of one and two point shots the team scored 92 points in all right and solve a system of equations to find out the number of each type of shot

There were 18 one point shots and 37 two point shots.

Step-by-step explanation:

Let the number of one point shots be x and the number of two point shots be y .

So we have the system:

x + y = 55

x + 2y = 92

Subtract the first equation from the second, we get:

0 + y = 92 - 55 = 37.  

y = 37.

From equation 1 we have x = 55 - y

therefore x = 55 - 37 = 18.

y=x+2 hope this jdjxhdnzbdjdo

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

one more happy customer!

< 3

step-by-step explanation: