Wanahton is cooking a breadstick on a rectangular baking sheet measuring 9\dfrac129 2 1 9, start fraction, 1, divided by, 2, end fraction inches (\text{in})(in)left parenthesis, i, n, right parenthesis by 13\,\text{in}13in13, space, i, n. assuming the breadstick width is negligible, what is the longest breadstick wanahton could bake by fitting it straight along the diagonal and within the baking sheet to the nearest inch?

The longest bread stick is approximately 16 in

Explanation:

The diagram representing the tray is shown in the attached image

From the diagram, we can note that the diagonal of the tray represents the hypotenuse of a right-angled triangle having legs 9.5 in and 13 in

Therefore, to get the length of the hypotenuse, we can use the Pythagorean equation which is as follows:

c² = a² + b²

where c is the length of the hypotenuse and a and b are the length of the two legs

Substitute with the givens in the above equation to get the length of the hypotenuse as follows:

c² = (9.5)² + (13)² = 259.25

c = 16.1 in which is approximately 16 in

From the above, we can conclude that:

The longest bread stick that can be fit straight along the diagonal of the tray is approximately 16 in

Hope this helps :)

3x + 18 = 147°

step-by-step explanation:

3x + 18 = 147°, because the value of the central angle is equal to the value of the arc formed by it.

i hope i you.