Bcd is a right triangle. the length of the hypotenuse is 22 cm. the length of one of the legs is 18 cm. what is the length of the other leg? enter your answer in the box as a decimal rounded to the nearest tenth. cm

Use (leg)^2 + (leg)^2 = (hyp)^2.

(18)^2 + (leg)^2 = (22)^2

(leg)^2 = 484 - 324

(leg)^2 = 160

Taking the square root on both sides we get leg = sqrt{160}.

The length of the other leg is sqrt{160} cm.

The answer must be given in decimal form.

sqrt{160} = 12.6491106407

We now round to the nearest tenth to find a final answer of 12.60 cm.

step-by-step explanation:

quartic functions has x = –1 and x = –2 as its only two real zeroes:

f(x) = a(x+2)(x+1)   a: real number

225x²+4=0

225x²=0-4

225x²=-4

x²=-4/225

x=±√-4/225