15 pts awarded and brainliest will be ! which of the following is the solution to | x+11 |< 17?

A. x < 6 and x > - 28

Step-by-step explanation:

We have been given the following inequality;

| x+11 | < 17

We can replace the absolute value function by re-writing the inequality as;

-17< x+11<17

subtract 11 from both sides;

-17-11<x+11-11<17-11

-28<x<6

splitting this we have;

x<6

x>-28

A. x < 6 and x > - 28

Step-by-step explanation:

| x+11 |< 17

x + 11 < 17

x < 6

-(x + 11) < 17

-x - 11 < 17

-x < 28

x > - 28

Answer

6 > x > -28 (x < 6 and x > - 28)

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.