What is the solution set of x² + 5 x + 1 = 0 hurry im taking a test

Step-by-step explanation:

x² + 5 x + 1 = 0

note :

hello :  

the discriminat of each quadratic equation : ax²+bx+c=0 (a ≠ 0) is :

Δ = b² -4ac

1 )  Δ > 0  the equation has two reals solutions : x =  (-b±√Δ)/2a

2 ) Δ = 0 : one solution : x = -b/2a

3 ) Δ < 0 : no reals solutions

you have : a = 1   b=5  c= 1

calculate :  Δ

sample answer: you can determine whether each element of the domain is paired with exactly one element of the range. for example, if given a graph, you could use the vertical line test; if a vertical line intersects the graph more than once, then the relation that the graph represents is not a function.