What additional information do you need to prove that ∆lmo ≅ ∆lno by the hl theorem? a. lm ≅ ml b. ∠nlo ≅ ∠mlo c. om ≅ on d. ∠mol ≅ ∠nol

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

include a picture of the drawing in order for me to

step-by-step explanation:

this linear equation would have just one solution.

step-by-step explanation:

the reason why this would have one solution is that it is an expression with just one variable. since that variable is not raised to a power, it will always have just one solution.