Mathematics, 29.06.2019 16:20, paytonxxburns05
If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation h=-16t^2 +vt+ s , where h is in feet. if the object is propelled from a height of 8 feet with an initial velocity of 64 feet per seconds , it's height h is given by the equation h=-16t^2+64t+8 after how many seconds is the height 68 feet? the time is .
Answers: 2
Mathematics, 21.06.2019 13:00, markaylarowland8
Rewrite the hyperbolic equation 4y^2 -9x^2 +54x-8y-113=0
Answers: 1
Mathematics, 21.06.2019 20:00, stonerbabyy
Someone answer asap for ! the boiling point of water at an elevation of 0 feet is 212 degrees fahrenheit (°f). for every 1,000 feet of increase in elevation, the boiling point of water decreases by about 2°f. which of the following represents this relationship if b is the boiling point of water at an elevation of e thousand feet? a. e = 2b - 212 b. b = 2e - 212 c. e = -2b + 212 d. b = -2e + 212
Answers: 1
If an object is propelled upward from a height of s feet at an initial velocity of v feet per second...
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